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135543441113141 is a prime number
BaseRepresentation
bin11110110100011010101010…
…101010001100000000110101
3122202220211022110110022201212
4132310122222222030000311
5120231220431411110031
61200135444111331205
740356455553544025
oct3664325252140065
9582824273408655
10135543441113141
113a208717997486
1213251288220b05
135a828cb738999
1425684a2365a85
1510a0be155e12b
hex7b46aaa8c035

135543441113141 has 2 divisors, whose sum is σ = 135543441113142. Its totient is φ = 135543441113140.

The previous prime is 135543441113077. The next prime is 135543441113161. The reversal of 135543441113141 is 141311144345531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 77562297846916 + 57981143266225 = 8806946^2 + 7614535^2 .

It is a cyclic number.

It is not a de Polignac number, because 135543441113141 - 26 = 135543441113077 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (135543441113161) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67771720556570 + 67771720556571.

It is an arithmetic number, because the mean of its divisors is an integer number (67771720556571).

Almost surely, 2135543441113141 is an apocalyptic number.

It is an amenable number.

135543441113141 is a deficient number, since it is larger than the sum of its proper divisors (1).

135543441113141 is an equidigital number, since it uses as much as digits as its factorization.

135543441113141 is an evil number, because the sum of its binary digits is even.

The product of its digits is 172800, while the sum is 41.

Adding to 135543441113141 its reverse (141311144345531), we get a palindrome (276854585458672).

The spelling of 135543441113141 in words is "one hundred thirty-five trillion, five hundred forty-three billion, four hundred forty-one million, one hundred thirteen thousand, one hundred forty-one".