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135545003144142 = 2323753951072869
BaseRepresentation
bin11110110100011100000111…
…110000110111001111001110
3122202220222100022200201102220
4132310130013300313033032
5120231232131301103032
61200140303111200210
740356542351565204
oct3664340760671716
9582828308621386
10135545003144142
113a209349695499
1213251643376066
135a82aba239497
1425685ad9b5074
1510a0c8375d12c
hex7b4707c373ce

135545003144142 has 16 divisors (see below), whose sum is σ = 271101419447760. Its totient is φ = 45179765521472.

The previous prime is 135545003144137. The next prime is 135545003144179. The reversal of 135545003144142 is 241441300545531.

It is a junction number, because it is equal to n+sod(n) for n = 135545003144094 and 135545003144103.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 475393917 + ... + 475678952.

It is an arithmetic number, because the mean of its divisors is an integer number (16943838715485).

Almost surely, 2135545003144142 is an apocalyptic number.

135545003144142 is an abundant number, since it is smaller than the sum of its proper divisors (135556416303618).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

135545003144142 is a wasteful number, since it uses less digits than its factorization.

135545003144142 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 951096627.

The product of its (nonzero) digits is 576000, while the sum is 42.

Adding to 135545003144142 its reverse (241441300545531), we get a palindrome (376986303689673).

The spelling of 135545003144142 in words is "one hundred thirty-five trillion, five hundred forty-five billion, three million, one hundred forty-four thousand, one hundred forty-two".

Divisors: 1 2 3 6 23753 47506 71259 142518 951072869 1902145738 2853218607 5706437214 22590833857357 45181667714714 67772501572071 135545003144142