135546953 has 2 divisors, whose sum is σ = 135546954. Its totient is φ = 135546952.

The previous prime is 135546937. The next prime is 135546959. The reversal of 135546953 is 359645531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 95199049 + 40347904 = 9757^2 + 6352^2 .

It is a cyclic number.

It is not a de Polignac number, because 135546953 - 2⁴ = 135546937 is a prime.

It is a Chen prime.

It is equal to p_7674656 and since 135546953 and 7674656 have the same sum of digits, it is a Honaker prime.

It is a self number, because there is not a number n which added to its sum of digits gives 135546953.

It is not a weakly prime, because it can be changed into another prime (135546959) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67773476 + 67773477.

It is an arithmetic number, because the mean of its divisors is an integer number (67773477).

Almost surely, 2^135546953 is an apocalyptic number.

It is an amenable number.

135546953 is a deficient number, since it is larger than the sum of its proper divisors (1).

135546953 is an equidigital number, since it uses as much as digits as its factorization.

135546953 is an evil number, because the sum of its binary digits is even.

The product of its digits is 243000, while the sum is 41.

The square root of 135546953 is about 11642.4633561803. The cubic root of 135546953 is about 513.6846478677.

The spelling of 135546953 in words is "one hundred thirty-five million, five hundred forty-six thousand, nine hundred fifty-three".