Base | Representation |
---|---|
bin | 1100010101000000011001… |
… | …0000000001010001010011 |
3 | 1202222211212202122121112002 |
4 | 3011100012100001101103 |
5 | 3234041141020231404 |
6 | 44455031352424215 |
7 | 2566214033645606 |
oct | 305200620012123 |
9 | 52884782577462 |
10 | 13555021648979 |
11 | 435671a384468 |
12 | 162b0793a806b |
13 | 774305044625 |
14 | 34c0d087433d |
15 | 1878e5940c1e |
hex | c5406401453 |
13555021648979 has 2 divisors, whose sum is σ = 13555021648980. Its totient is φ = 13555021648978.
The previous prime is 13555021648943. The next prime is 13555021648991. The reversal of 13555021648979 is 97984612055531.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13555021648979 is a prime.
It is a super-2 number, since 2×135550216489792 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13555021648079) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6777510824489 + 6777510824490.
It is an arithmetic number, because the mean of its divisors is an integer number (6777510824490).
It is a 1-persistent number, because it is pandigital, but 2⋅13555021648979 = 27110043297958 is not.
Almost surely, 213555021648979 is an apocalyptic number.
13555021648979 is a deficient number, since it is larger than the sum of its proper divisors (1).
13555021648979 is an equidigital number, since it uses as much as digits as its factorization.
13555021648979 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81648000, while the sum is 65.
The spelling of 13555021648979 in words is "thirteen trillion, five hundred fifty-five billion, twenty-one million, six hundred forty-eight thousand, nine hundred seventy-nine".
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