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135550401040049 is a prime number
BaseRepresentation
bin11110110100100001001001…
…100000001100111010110001
3122202221111021111210020120112
4132310201021200030322301
5120231324210131240144
61200142554454551105
740360123205132102
oct3664411140147261
9582844244706515
10135550401040049
113a210669660596
12132526ab068495
135a8346a650a28
1425689628503a9
1510a0e9c5ae99e
hex7b484980ceb1

135550401040049 has 2 divisors, whose sum is σ = 135550401040050. Its totient is φ = 135550401040048.

The previous prime is 135550401040031. The next prime is 135550401040097. The reversal of 135550401040049 is 940040104055531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 94600230850225 + 40950170189824 = 9726265^2 + 6399232^2 .

It is a cyclic number.

It is not a de Polignac number, because 135550401040049 - 212 = 135550401035953 is a prime.

It is a super-2 number, since 2×1355504010400492 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 135550401039988 and 135550401040015.

It is not a weakly prime, because it can be changed into another prime (135550401040099) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67775200520024 + 67775200520025.

It is an arithmetic number, because the mean of its divisors is an integer number (67775200520025).

Almost surely, 2135550401040049 is an apocalyptic number.

It is an amenable number.

135550401040049 is a deficient number, since it is larger than the sum of its proper divisors (1).

135550401040049 is an equidigital number, since it uses as much as digits as its factorization.

135550401040049 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216000, while the sum is 41.

The spelling of 135550401040049 in words is "one hundred thirty-five trillion, five hundred fifty billion, four hundred one million, forty thousand, forty-nine".