135550401124153 has 2 divisors, whose sum is σ = 135550401124154. Its totient is φ = 135550401124152.

The previous prime is 135550401124121. The next prime is 135550401124163. The reversal of 135550401124153 is 351421104055531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 81154657753744 + 54395743370409 = 9008588^2 + 7375347^2 .

It is a cyclic number.

It is not a de Polignac number, because 135550401124153 - 2⁵ = 135550401124121 is a prime.

It is a super-2 number, since 2×135550401124153² (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (135550401124163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67775200562076 + 67775200562077.

It is an arithmetic number, because the mean of its divisors is an integer number (67775200562077).

Almost surely, 2^{135550401124153} is an apocalyptic number.

It is an amenable number.

135550401124153 is a deficient number, since it is larger than the sum of its proper divisors (1).

135550401124153 is an equidigital number, since it uses as much as digits as its factorization.

135550401124153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 180000, while the sum is 40.

Adding to 135550401124153 its reverse (351421104055531), we get a palindrome (486971505179684).

The spelling of 135550401124153 in words is "one hundred thirty-five trillion, five hundred fifty billion, four hundred one million, one hundred twenty-four thousand, one hundred fifty-three".