Base | Representation |
---|---|
bin | 11110110100100001001011… |
… | …110100110100111100011111 |
3 | 122202221111101020002200101020 |
4 | 132310201023310310330133 |
5 | 120231324300120020221 |
6 | 1200143002410015223 |
7 | 40360124160242556 |
oct | 3664411364647437 |
9 | 582844336080336 |
10 | 135550440001311 |
11 | 3a210689651785 |
12 | 13252700117513 |
13 | 5a8347574282a |
14 | 2568967ab2d9d |
15 | 10a0ea0c08ac6 |
hex | 7b484bd34f1f |
135550440001311 has 4 divisors (see below), whose sum is σ = 180733920001752. Its totient is φ = 90366960000872.
The previous prime is 135550440001261. The next prime is 135550440001337. The reversal of 135550440001311 is 113100044055531.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 135550440001311 - 223 = 135550431612703 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (135550440001411) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22591740000216 + ... + 22591740000221.
It is an arithmetic number, because the mean of its divisors is an integer number (45183480000438).
Almost surely, 2135550440001311 is an apocalyptic number.
135550440001311 is a deficient number, since it is larger than the sum of its proper divisors (45183480000441).
135550440001311 is an equidigital number, since it uses as much as digits as its factorization.
135550440001311 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 45183480000440.
The product of its (nonzero) digits is 18000, while the sum is 33.
Adding to 135550440001311 its reverse (113100044055531), we get a palindrome (248650484056842).
The spelling of 135550440001311 in words is "one hundred thirty-five trillion, five hundred fifty billion, four hundred forty million, one thousand, three hundred eleven".
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