Base | Representation |
---|---|
bin | 111111000111101111… |
… | …1010011011011110011 |
3 | 110221212210202020102122 |
4 | 1332033133103123303 |
5 | 4210102120143011 |
6 | 142134343304455 |
7 | 12536042220653 |
oct | 1761737233363 |
9 | 427783666378 |
10 | 135551334131 |
11 | 5253a215684 |
12 | 2232ba4b12b |
13 | ca2301cc25 |
14 | 67bc886363 |
15 | 37d53c33db |
hex | 1f8f7d36f3 |
135551334131 has 2 divisors, whose sum is σ = 135551334132. Its totient is φ = 135551334130.
The previous prime is 135551334031. The next prime is 135551334199. The reversal of 135551334131 is 131433155531.
It is a strong prime.
It is an emirp because it is prime and its reverse (131433155531) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 135551334131 - 214 = 135551317747 is a prime.
It is a super-2 number, since 2×1355513341312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 135551334091 and 135551334100.
It is not a weakly prime, because it can be changed into another prime (135551334031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67775667065 + 67775667066.
It is an arithmetic number, because the mean of its divisors is an integer number (67775667066).
Almost surely, 2135551334131 is an apocalyptic number.
135551334131 is a deficient number, since it is larger than the sum of its proper divisors (1).
135551334131 is an equidigital number, since it uses as much as digits as its factorization.
135551334131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 40500, while the sum is 35.
Adding to 135551334131 its reverse (131433155531), we get a palindrome (266984489662).
The spelling of 135551334131 in words is "one hundred thirty-five billion, five hundred fifty-one million, three hundred thirty-four thousand, one hundred thirty-one".
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