Base | Representation |
---|---|
bin | 11110110100100011110001… |
… | …001110101000001000010011 |
3 | 122202221202112121202111002011 |
4 | 132310203301032220020103 |
5 | 120231400441020131303 |
6 | 1200144142020003351 |
7 | 40360253014343122 |
oct | 3664436116501023 |
9 | 582852477674064 |
10 | 135553215005203 |
11 | 3a211883007226 |
12 | 13253155530557 |
13 | 5a837c862a578 |
14 | 2568b4c46bab9 |
15 | 10a10b465716d |
hex | 7b48f13a8213 |
135553215005203 has 2 divisors, whose sum is σ = 135553215005204. Its totient is φ = 135553215005202.
The previous prime is 135553215005171. The next prime is 135553215005213. The reversal of 135553215005203 is 302500512355531.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 135553215005203 - 25 = 135553215005171 is a prime.
It is not a weakly prime, because it can be changed into another prime (135553215005213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67776607502601 + 67776607502602.
It is an arithmetic number, because the mean of its divisors is an integer number (67776607502602).
Almost surely, 2135553215005203 is an apocalyptic number.
135553215005203 is a deficient number, since it is larger than the sum of its proper divisors (1).
135553215005203 is an equidigital number, since it uses as much as digits as its factorization.
135553215005203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 337500, while the sum is 40.
The spelling of 135553215005203 in words is "one hundred thirty-five trillion, five hundred fifty-three billion, two hundred fifteen million, five thousand, two hundred three".
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