Base | Representation |
---|---|
bin | 1100010101000001100011… |
… | …0001100001100111010111 |
3 | 1202222212200102102112002210 |
4 | 3011100120301201213113 |
5 | 3234042310100001403 |
6 | 44455122253404503 |
7 | 2566224526324653 |
oct | 305203061414727 |
9 | 52885612375083 |
10 | 13555332422103 |
11 | 435686984695a |
12 | 162b145499733 |
13 | 774354544b54 |
14 | 34c11dc4da63 |
15 | 187912d7bb03 |
hex | c5418c619d7 |
13555332422103 has 8 divisors (see below), whose sum is σ = 18073974299248. Its totient is φ = 9036789413184.
The previous prime is 13555332422077. The next prime is 13555332422111. The reversal of 13555332422103 is 30122423355531.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13555332422103 - 210 = 13555332421079 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13555332422183) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 24396550 + ... + 24945987.
It is an arithmetic number, because the mean of its divisors is an integer number (2259246787406).
Almost surely, 213555332422103 is an apocalyptic number.
13555332422103 is a deficient number, since it is larger than the sum of its proper divisors (4518641877145).
13555332422103 is an equidigital number, since it uses as much as digits as its factorization.
13555332422103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 49434113.
The product of its (nonzero) digits is 324000, while the sum is 39.
Adding to 13555332422103 its reverse (30122423355531), we get a palindrome (43677755777634).
The spelling of 13555332422103 in words is "thirteen trillion, five hundred fifty-five billion, three hundred thirty-two million, four hundred twenty-two thousand, one hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •