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13555332422111 is a prime number
BaseRepresentation
bin1100010101000001100011…
…0001100001100111011111
31202222212200102102112010002
43011100120301201213133
53234042310100001421
644455122253404515
72566224526324664
oct305203061414737
952885612375102
1013555332422111
114356869846967
12162b14549973b
13774354544b5c
1434c11dc4da6b
15187912d7bb0b
hexc5418c619df

13555332422111 has 2 divisors, whose sum is σ = 13555332422112. Its totient is φ = 13555332422110.

The previous prime is 13555332422077. The next prime is 13555332422161. The reversal of 13555332422111 is 11122423355531.

It is a weak prime.

It is an emirp because it is prime and its reverse (11122423355531) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13555332422111 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13555332422161) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6777666211055 + 6777666211056.

It is an arithmetic number, because the mean of its divisors is an integer number (6777666211056).

Almost surely, 213555332422111 is an apocalyptic number.

13555332422111 is a deficient number, since it is larger than the sum of its proper divisors (1).

13555332422111 is an equidigital number, since it uses as much as digits as its factorization.

13555332422111 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 108000, while the sum is 38.

Adding to 13555332422111 its reverse (11122423355531), we get a palindrome (24677755777642).

The spelling of 13555332422111 in words is "thirteen trillion, five hundred fifty-five billion, three hundred thirty-two million, four hundred twenty-two thousand, one hundred eleven".