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1355545121101 = 3143727261971
BaseRepresentation
bin10011101110011100110…
…010010001000101001101
311210120220021021221222121
4103232130302101011031
5134202124022333401
62514421232212541
7166635446263063
oct23563462210515
94716807257877
101355545121101
11482979977856
1219a86939a151
139aa9a9185c2
144987451a033
15253da4edca1
hex13b9cc9114d

1355545121101 has 4 divisors (see below), whose sum is σ = 1399272383104. Its totient is φ = 1311817859100.

The previous prime is 1355545121087. The next prime is 1355545121113. The reversal of 1355545121101 is 1011215455531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1355545121101 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1355545121201) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21863630955 + ... + 21863631016.

It is an arithmetic number, because the mean of its divisors is an integer number (349818095776).

Almost surely, 21355545121101 is an apocalyptic number.

It is an amenable number.

1355545121101 is a deficient number, since it is larger than the sum of its proper divisors (43727262003).

1355545121101 is an equidigital number, since it uses as much as digits as its factorization.

1355545121101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 43727262002.

The product of its (nonzero) digits is 15000, while the sum is 34.

The spelling of 1355545121101 in words is "one trillion, three hundred fifty-five billion, five hundred forty-five million, one hundred twenty-one thousand, one hundred one".

Divisors: 1 31 43727261971 1355545121101