Base | Representation |
---|---|
bin | 1100010101000010001110… |
… | …0010011010011111100111 |
3 | 1202222220011000020100100000 |
4 | 3011100203202122133213 |
5 | 3234043142312311101 |
6 | 44455152224152343 |
7 | 2566232151312510 |
oct | 305204342323747 |
9 | 52886130210300 |
10 | 13555513010151 |
11 | 4356951780382 |
12 | 162b195a686b3 |
13 | 774382a93598 |
14 | 34c139c1ba07 |
15 | 187923b4e486 |
hex | c542389a7e7 |
13555513010151 has 24 divisors (see below), whose sum is σ = 23206145732224. Its totient is φ = 7746007433400.
The previous prime is 13555513010129. The next prime is 13555513010197. The reversal of 13555513010151 is 15101031555531.
13555513010151 is a `hidden beast` number, since 1 + 3 + 55 + 551 + 3 + 0 + 1 + 0 + 1 + 51 = 666.
13555513010151 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13555513010151 - 223 = 13555504621543 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13555513010251) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3984570025 + ... + 3984573426.
Almost surely, 213555513010151 is an apocalyptic number.
13555513010151 is a deficient number, since it is larger than the sum of its proper divisors (9650632722073).
13555513010151 is an frugal number, since it uses more digits than its factorization.
13555513010151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7969143473 (or 7969143461 counting only the distinct ones).
The product of its (nonzero) digits is 28125, while the sum is 36.
Adding to 13555513010151 its reverse (15101031555531), we get a palindrome (28656544565682).
The spelling of 13555513010151 in words is "thirteen trillion, five hundred fifty-five billion, five hundred thirteen million, ten thousand, one hundred fifty-one".
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