Base | Representation |
---|---|
bin | 11110110100100101111101… |
… | …010011000110011111111011 |
3 | 122202221222121101200000000021 |
4 | 132310211331103012133323 |
5 | 120231420244114112121 |
6 | 1200145211124151311 |
7 | 40360365161022121 |
oct | 3664457523063773 |
9 | 582858541600007 |
10 | 135555564988411 |
11 | 3a212879567407 |
12 | 132536b0538537 |
13 | 5a83ab1453289 |
14 | 2568cd25cb911 |
15 | 10a11a0aed641 |
hex | 7b497d4c67fb |
135555564988411 has 2 divisors, whose sum is σ = 135555564988412. Its totient is φ = 135555564988410.
The previous prime is 135555564988373. The next prime is 135555564988577. The reversal of 135555564988411 is 114889465555531.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 135555564988411 - 213 = 135555564980219 is a prime.
It is a super-2 number, since 2×1355555649884112 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (135555564986411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67777782494205 + 67777782494206.
It is an arithmetic number, because the mean of its divisors is an integer number (67777782494206).
Almost surely, 2135555564988411 is an apocalyptic number.
135555564988411 is a deficient number, since it is larger than the sum of its proper divisors (1).
135555564988411 is an equidigital number, since it uses as much as digits as its factorization.
135555564988411 is an evil number, because the sum of its binary digits is even.
The product of its digits is 518400000, while the sum is 70.
The spelling of 135555564988411 in words is "one hundred thirty-five trillion, five hundred fifty-five billion, five hundred sixty-four million, nine hundred eighty-eight thousand, four hundred eleven".
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