135596443 has 2 divisors, whose sum is σ = 135596444. Its totient is φ = 135596442.

The previous prime is 135596423. The next prime is 135596459. The reversal of 135596443 is 344695531.

It is a strong prime.

It is an emirp because it is prime and its reverse (344695531) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 135596443 - 2⁹ = 135595931 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 135596396 and 135596405.

It is not a weakly prime, because it can be changed into another prime (135596423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67798221 + 67798222.

It is an arithmetic number, because the mean of its divisors is an integer number (67798222).

Almost surely, 2^135596443 is an apocalyptic number.

135596443 is a deficient number, since it is larger than the sum of its proper divisors (1).

135596443 is an equidigital number, since it uses as much as digits as its factorization.

135596443 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 194400, while the sum is 40.

The square root of 135596443 is about 11644.5885715211. The cubic root of 135596443 is about 513.7471579654.

It can be divided in two parts, 13559 and 6443, that added together give a palindrome (20002).

The spelling of 135596443 in words is "one hundred thirty-five million, five hundred ninety-six thousand, four hundred forty-three".