Base | Representation |
---|---|
bin | 10011101110111001111… |
… | …011010011111000100001 |
3 | 11210122011100021011110201 |
4 | 103232321323103320201 |
5 | 134204124202444022 |
6 | 2514541535225201 |
7 | 166653534040552 |
oct | 23567173237041 |
9 | 4718140234421 |
10 | 1356034031137 |
11 | 4830aa94a135 |
12 | 19a985078201 |
13 | 9ab47cb9996 |
14 | 498bd426329 |
15 | 254183c6127 |
hex | 13bb9ed3e21 |
1356034031137 has 2 divisors, whose sum is σ = 1356034031138. Its totient is φ = 1356034031136.
The previous prime is 1356034031057. The next prime is 1356034031161. The reversal of 1356034031137 is 7311304306531.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1257995532816 + 98038498321 = 1121604^2 + 313111^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1356034031137 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1356034031096 and 1356034031105.
It is not a weakly prime, because it can be changed into another prime (1356034031167) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 678017015568 + 678017015569.
It is an arithmetic number, because the mean of its divisors is an integer number (678017015569).
Almost surely, 21356034031137 is an apocalyptic number.
It is an amenable number.
1356034031137 is a deficient number, since it is larger than the sum of its proper divisors (1).
1356034031137 is an equidigital number, since it uses as much as digits as its factorization.
1356034031137 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 68040, while the sum is 37.
Adding to 1356034031137 its reverse (7311304306531), we get a palindrome (8667338337668).
The spelling of 1356034031137 in words is "one trillion, three hundred fifty-six billion, thirty-four million, thirty-one thousand, one hundred thirty-seven".
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