Base | Representation |
---|---|
bin | 10011101110111001111… |
… | …011101111000110011111 |
3 | 11210122011100110211101211 |
4 | 103232321323233012133 |
5 | 134204124220030443 |
6 | 2514541541445251 |
7 | 166653535013566 |
oct | 23567173570637 |
9 | 4718140424354 |
10 | 1356034142623 |
11 | 4830aaa15976 |
12 | 19a985110827 |
13 | 9ab48028654 |
14 | 498bd454bdd |
15 | 254183e919d |
hex | 13bb9eef19f |
1356034142623 has 4 divisors (see below), whose sum is σ = 1414992148848. Its totient is φ = 1297076136400.
The previous prime is 1356034142591. The next prime is 1356034142681. The reversal of 1356034142623 is 3262414306531.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1356034142623 - 25 = 1356034142591 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1356034142123) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29479003078 + ... + 29479003123.
It is an arithmetic number, because the mean of its divisors is an integer number (353748037212).
Almost surely, 21356034142623 is an apocalyptic number.
1356034142623 is a deficient number, since it is larger than the sum of its proper divisors (58958006225).
1356034142623 is an equidigital number, since it uses as much as digits as its factorization.
1356034142623 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 58958006224.
The product of its (nonzero) digits is 311040, while the sum is 40.
The spelling of 1356034142623 in words is "one trillion, three hundred fifty-six billion, thirty-four million, one hundred forty-two thousand, six hundred twenty-three".
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