1356034142681 has 2 divisors, whose sum is σ = 1356034142682. Its totient is φ = 1356034142680.

The previous prime is 1356034142591. The next prime is 1356034142689. The reversal of 1356034142681 is 1862414306531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 784889683600 + 571144459081 = 885940^2 + 755741^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1356034142681 is a prime.

It is a super-2 number, since 2×1356034142681² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1356034142689) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 678017071340 + 678017071341.

It is an arithmetic number, because the mean of its divisors is an integer number (678017071341).

Almost surely, 2^{1356034142681} is an apocalyptic number.

It is an amenable number.

1356034142681 is a deficient number, since it is larger than the sum of its proper divisors (1).

1356034142681 is an equidigital number, since it uses as much as digits as its factorization.

1356034142681 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 414720, while the sum is 44.

The spelling of 1356034142681 in words is "one trillion, three hundred fifty-six billion, thirty-four million, one hundred forty-two thousand, six hundred eighty-one".