Base | Representation |
---|---|
bin | 11110110101010011001001… |
… | …000010111111101011011101 |
3 | 122210010121211112010001212012 |
4 | 132311103021002333223131 |
5 | 120233214124100143340 |
6 | 1200223353215321005 |
7 | 40364033345610023 |
oct | 3665231102775335 |
9 | 583117745101765 |
10 | 135604080474845 |
11 | 3a231405267444 |
12 | 13260b90220165 |
13 | 5a885437938b8 |
14 | 256b3b5aca713 |
15 | 10a258eea7565 |
hex | 7b54c90bfadd |
135604080474845 has 32 divisors (see below), whose sum is σ = 163422764524032. Its totient is φ = 108019133494272.
The previous prime is 135604080474829. The next prime is 135604080474847. The reversal of 135604080474845 is 548474080406531.
It is a cyclic number.
It is not a de Polignac number, because 135604080474845 - 24 = 135604080474829 is a prime.
It is a super-3 number, since 3×1356040804748453 (a number of 43 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (135604080474847) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4879059269 + ... + 4879087061.
It is an arithmetic number, because the mean of its divisors is an integer number (5106961391376).
Almost surely, 2135604080474845 is an apocalyptic number.
It is an amenable number.
135604080474845 is a deficient number, since it is larger than the sum of its proper divisors (27818684049187).
135604080474845 is a wasteful number, since it uses less digits than its factorization.
135604080474845 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 32661.
The product of its (nonzero) digits is 51609600, while the sum is 59.
The spelling of 135604080474845 in words is "one hundred thirty-five trillion, six hundred four billion, eighty million, four hundred seventy-four thousand, eight hundred forty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •