Search a number
-
+
1356047339 is a prime number
BaseRepresentation
bin101000011010011…
…1010001111101011
310111111122100020112
41100310322033223
510234122003324
6342320444535
745414132533
oct12064721753
93444570215
101356047339
116364a9489
1231a17974b
13187c2ca9a
14cc1504c3
157e0b1c0e
hex50d3a3eb

1356047339 has 2 divisors, whose sum is σ = 1356047340. Its totient is φ = 1356047338.

The previous prime is 1356047239. The next prime is 1356047351. The reversal of 1356047339 is 9337406531.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1356047339 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1356047296 and 1356047305.

It is not a weakly prime, because it can be changed into another prime (1356047369) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 678023669 + 678023670.

It is an arithmetic number, because the mean of its divisors is an integer number (678023670).

Almost surely, 21356047339 is an apocalyptic number.

1356047339 is a deficient number, since it is larger than the sum of its proper divisors (1).

1356047339 is an equidigital number, since it uses as much as digits as its factorization.

1356047339 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 204120, while the sum is 41.

The square root of 1356047339 is about 36824.5480488220. The cubic root of 1356047339 is about 1106.8572573089.

The spelling of 1356047339 in words is "one billion, three hundred fifty-six million, forty-seven thousand, three hundred thirty-nine".