Base | Representation |
---|---|
bin | 111111001001011000… |
… | …1111111011100001111 |
3 | 110222000122200020102102 |
4 | 1332102301333130033 |
5 | 4210210240031443 |
6 | 142144035145315 |
7 | 12540312531545 |
oct | 1762261773417 |
9 | 428018606372 |
10 | 135606564623 |
11 | 52568409112 |
12 | 2234644523b |
13 | ca315b9caa |
14 | 67c5d41d95 |
15 | 37da182cb8 |
hex | 1f92c7f70f |
135606564623 has 4 divisors (see below), whose sum is σ = 135818119968. Its totient is φ = 135395009280.
The previous prime is 135606564617. The next prime is 135606564649. The reversal of 135606564623 is 326465606531.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 135606564623 - 212 = 135606560527 is a prime.
It is a super-3 number, since 3×1356065646233 (a number of 34 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (135606564923) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 105776711 + ... + 105777992.
It is an arithmetic number, because the mean of its divisors is an integer number (33954529992).
Almost surely, 2135606564623 is an apocalyptic number.
135606564623 is a deficient number, since it is larger than the sum of its proper divisors (211555345).
135606564623 is an equidigital number, since it uses as much as digits as its factorization.
135606564623 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 211555344.
The product of its (nonzero) digits is 2332800, while the sum is 47.
The spelling of 135606564623 in words is "one hundred thirty-five billion, six hundred six million, five hundred sixty-four thousand, six hundred twenty-three".
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