Search a number
-
+
135684138867097 is a prime number
BaseRepresentation
bin11110110110011101101100…
…111001100001100110011001
3122210102021110221002202222011
4132312131230321201212121
5120241022104022221342
61200324233300425521
740402566306661312
oct3666355471414631
9583367427082864
10135684138867097
113a262358126487
12132745b36a82a1
135a92c61a31932
14257120c505609
1510a46c865c717
hex7b676ce61999

135684138867097 has 2 divisors, whose sum is σ = 135684138867098. Its totient is φ = 135684138867096.

The previous prime is 135684138867089. The next prime is 135684138867157. The reversal of 135684138867097 is 790768831486531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 75819581013136 + 59864557853961 = 8707444^2 + 7737219^2 .

It is a cyclic number.

It is not a de Polignac number, because 135684138867097 - 23 = 135684138867089 is a prime.

It is a super-3 number, since 3×1356841388670973 (a number of 43 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (135684198867097) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67842069433548 + 67842069433549.

It is an arithmetic number, because the mean of its divisors is an integer number (67842069433549).

Almost surely, 2135684138867097 is an apocalyptic number.

It is an amenable number.

135684138867097 is a deficient number, since it is larger than the sum of its proper divisors (1).

135684138867097 is an equidigital number, since it uses as much as digits as its factorization.

135684138867097 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1463132160, while the sum is 76.

The spelling of 135684138867097 in words is "one hundred thirty-five trillion, six hundred eighty-four billion, one hundred thirty-eight million, eight hundred sixty-seven thousand, ninety-seven".