Base | Representation |
---|---|
bin | 1100010101111101010001… |
… | …1010011111110111101011 |
3 | 1210001102001210022101202021 |
4 | 3011133110122133313223 |
5 | 3234323124020413024 |
6 | 44510333232045311 |
7 | 2600333041403554 |
oct | 305372432376753 |
9 | 53042053271667 |
10 | 13571365404139 |
11 | 4362646a69634 |
12 | 163227a993837 |
13 | 775a0b0a847a |
14 | 34cc0132932b |
15 | 1880506d9de4 |
hex | c57d469fdeb |
13571365404139 has 2 divisors, whose sum is σ = 13571365404140. Its totient is φ = 13571365404138.
The previous prime is 13571365404089. The next prime is 13571365404161. The reversal of 13571365404139 is 93140456317531.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13571365404139 - 27 = 13571365404011 is a prime.
It is not a weakly prime, because it can be changed into another prime (13571365404439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6785682702069 + 6785682702070.
It is an arithmetic number, because the mean of its divisors is an integer number (6785682702070).
Almost surely, 213571365404139 is an apocalyptic number.
13571365404139 is a deficient number, since it is larger than the sum of its proper divisors (1).
13571365404139 is an equidigital number, since it uses as much as digits as its factorization.
13571365404139 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4082400, while the sum is 52.
The spelling of 13571365404139 in words is "thirteen trillion, five hundred seventy-one billion, three hundred sixty-five million, four hundred four thousand, one hundred thirty-nine".
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