Base | Representation |
---|---|
bin | 11110110110111111001110… |
… | …101001110101011110100011 |
3 | 122210112201101211001201120212 |
4 | 132312333032221311132203 |
5 | 120242114320444102442 |
6 | 1200352545421124335 |
7 | 40405312362113105 |
oct | 3666771651653643 |
9 | 583481354051525 |
10 | 135720138659747 |
11 | 3a276651069534 |
12 | 1327b57b9b96ab |
13 | 5a9647b11c2a5 |
14 | 2572c65707575 |
15 | 10a55d3d7ca82 |
hex | 7b6fcea757a3 |
135720138659747 has 2 divisors, whose sum is σ = 135720138659748. Its totient is φ = 135720138659746.
The previous prime is 135720138659741. The next prime is 135720138659797. The reversal of 135720138659747 is 747956831027531.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 135720138659747 - 28 = 135720138659491 is a prime.
It is not a weakly prime, because it can be changed into another prime (135720138659741) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67860069329873 + 67860069329874.
It is an arithmetic number, because the mean of its divisors is an integer number (67860069329874).
It is a 1-persistent number, because it is pandigital, but 2⋅135720138659747 = 271440277319494 is not.
Almost surely, 2135720138659747 is an apocalyptic number.
135720138659747 is a deficient number, since it is larger than the sum of its proper divisors (1).
135720138659747 is an equidigital number, since it uses as much as digits as its factorization.
135720138659747 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 266716800, while the sum is 68.
The spelling of 135720138659747 in words is "one hundred thirty-five trillion, seven hundred twenty billion, one hundred thirty-eight million, six hundred fifty-nine thousand, seven hundred forty-seven".
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