Base | Representation |
---|---|
bin | 11110110111001001101010… |
… | …010100001110001100000011 |
3 | 122210120210022110200121112012 |
4 | 132313021222110032030003 |
5 | 120242310241041032313 |
6 | 1200402041124323135 |
7 | 40406160066321233 |
oct | 3667115224161403 |
9 | 583523273617465 |
10 | 135731340174083 |
11 | 3a28037a023aa5 |
12 | 132817872434ab |
13 | 5a97544a11294 |
14 | 2573609271cc3 |
15 | 10a5a3c474da8 |
hex | 7b726a50e303 |
135731340174083 has 2 divisors, whose sum is σ = 135731340174084. Its totient is φ = 135731340174082.
The previous prime is 135731340174077. The next prime is 135731340174193. The reversal of 135731340174083 is 380471043137531.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 135731340174083 - 210 = 135731340173059 is a prime.
It is not a weakly prime, because it can be changed into another prime (135731340144083) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67865670087041 + 67865670087042.
It is an arithmetic number, because the mean of its divisors is an integer number (67865670087042).
Almost surely, 2135731340174083 is an apocalyptic number.
135731340174083 is a deficient number, since it is larger than the sum of its proper divisors (1).
135731340174083 is an equidigital number, since it uses as much as digits as its factorization.
135731340174083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2540160, while the sum is 50.
The spelling of 135731340174083 in words is "one hundred thirty-five trillion, seven hundred thirty-one billion, three hundred forty million, one hundred seventy-four thousand, eighty-three".
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