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13574774113 is a prime number
BaseRepresentation
bin11001010010001111…
…01001110101100001
31022001001022222022121
430221013221311201
5210300120232423
610123002304241
7660252450625
oct145107516541
938031288277
1013574774113
11583667378a
12276a1b8081
1313844a7624
1492ac27185
15546b3a45d
hex3291e9d61

13574774113 has 2 divisors, whose sum is σ = 13574774114. Its totient is φ = 13574774112.

The previous prime is 13574774077. The next prime is 13574774117. The reversal of 13574774113 is 31147747531.

13574774113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13195576384 + 379197729 = 114872^2 + 19473^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13574774113 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13574774113.

It is not a weakly prime, because it can be changed into another prime (13574774117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6787387056 + 6787387057.

It is an arithmetic number, because the mean of its divisors is an integer number (6787387057).

Almost surely, 213574774113 is an apocalyptic number.

It is an amenable number.

13574774113 is a deficient number, since it is larger than the sum of its proper divisors (1).

13574774113 is an equidigital number, since it uses as much as digits as its factorization.

13574774113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 246960, while the sum is 43.

The spelling of 13574774113 in words is "thirteen billion, five hundred seventy-four million, seven hundred seventy-four thousand, one hundred thirteen".