Base | Representation |
---|---|
bin | 111111001110010110… |
… | …1110011111010111001 |
3 | 110222110021022021110012 |
4 | 1332130231303322321 |
5 | 4211030422203032 |
6 | 142212351431305 |
7 | 12544405335551 |
oct | 1763455637271 |
9 | 428407267405 |
10 | 135773241017 |
11 | 526435005a7 |
12 | 22392225535 |
13 | ca59ca758b |
14 | 680012c161 |
15 | 37e9b086b2 |
hex | 1f9cb73eb9 |
135773241017 has 2 divisors, whose sum is σ = 135773241018. Its totient is φ = 135773241016.
The previous prime is 135773241001. The next prime is 135773241031. The reversal of 135773241017 is 710142377531.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 128611173376 + 7162067641 = 358624^2 + 84629^2 .
It is an emirp because it is prime and its reverse (710142377531) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 135773241017 - 24 = 135773241001 is a prime.
It is not a weakly prime, because it can be changed into another prime (135773241817) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67886620508 + 67886620509.
It is an arithmetic number, because the mean of its divisors is an integer number (67886620509).
Almost surely, 2135773241017 is an apocalyptic number.
It is an amenable number.
135773241017 is a deficient number, since it is larger than the sum of its proper divisors (1).
135773241017 is an equidigital number, since it uses as much as digits as its factorization.
135773241017 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 123480, while the sum is 41.
The spelling of 135773241017 in words is "one hundred thirty-five billion, seven hundred seventy-three million, two hundred forty-one thousand, seventeen".
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