Base | Representation |
---|---|
bin | 111111001111001011… |
… | …1110001001100011001 |
3 | 110222112012120110002111 |
4 | 1332132113301030121 |
5 | 4211110030021423 |
6 | 142215223032321 |
7 | 12545163412456 |
oct | 1763627611431 |
9 | 428465513074 |
10 | 135801017113 |
11 | 52658152153 |
12 | 2239b59b6a1 |
13 | ca62981238 |
14 | 6803abc82d |
15 | 37ec29360d |
hex | 1f9e5f1319 |
135801017113 has 2 divisors, whose sum is σ = 135801017114. Its totient is φ = 135801017112.
The previous prime is 135801016997. The next prime is 135801017123. The reversal of 135801017113 is 311710108531.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 123656315904 + 12144701209 = 351648^2 + 110203^2 .
It is a cyclic number.
It is not a de Polignac number, because 135801017113 - 221 = 135798919961 is a prime.
It is not a weakly prime, because it can be changed into another prime (135801017123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67900508556 + 67900508557.
It is an arithmetic number, because the mean of its divisors is an integer number (67900508557).
Almost surely, 2135801017113 is an apocalyptic number.
It is an amenable number.
135801017113 is a deficient number, since it is larger than the sum of its proper divisors (1).
135801017113 is an equidigital number, since it uses as much as digits as its factorization.
135801017113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2520, while the sum is 31.
The spelling of 135801017113 in words is "one hundred thirty-five billion, eight hundred one million, seventeen thousand, one hundred thirteen".
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