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135847172113 is a prime number
BaseRepresentation
bin111111010000100011…
…1110101100000010001
3110222122102102100211221
41332201013311200101
54211203334001423
6142223552205041
712546263624242
oct1764107654021
9428572370757
10135847172113
1152681207084
12223b2b39781
13ca6c3c14a3
146809c94cc9
15380135de5d
hex1fa11f5811

135847172113 has 2 divisors, whose sum is σ = 135847172114. Its totient is φ = 135847172112.

The previous prime is 135847172107. The next prime is 135847172179. The reversal of 135847172113 is 311271748531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 86043662224 + 49803509889 = 293332^2 + 223167^2 .

It is a cyclic number.

It is not a de Polignac number, because 135847172113 - 217 = 135847041041 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 135847172113.

It is not a weakly prime, because it can be changed into another prime (135847172413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67923586056 + 67923586057.

It is an arithmetic number, because the mean of its divisors is an integer number (67923586057).

Almost surely, 2135847172113 is an apocalyptic number.

It is an amenable number.

135847172113 is a deficient number, since it is larger than the sum of its proper divisors (1).

135847172113 is an equidigital number, since it uses as much as digits as its factorization.

135847172113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 141120, while the sum is 43.

The spelling of 135847172113 in words is "one hundred thirty-five billion, eight hundred forty-seven million, one hundred seventy-two thousand, one hundred thirteen".