Base | Representation |
---|---|
bin | 111111010000100011… |
… | …1110101100000010001 |
3 | 110222122102102100211221 |
4 | 1332201013311200101 |
5 | 4211203334001423 |
6 | 142223552205041 |
7 | 12546263624242 |
oct | 1764107654021 |
9 | 428572370757 |
10 | 135847172113 |
11 | 52681207084 |
12 | 223b2b39781 |
13 | ca6c3c14a3 |
14 | 6809c94cc9 |
15 | 380135de5d |
hex | 1fa11f5811 |
135847172113 has 2 divisors, whose sum is σ = 135847172114. Its totient is φ = 135847172112.
The previous prime is 135847172107. The next prime is 135847172179. The reversal of 135847172113 is 311271748531.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 86043662224 + 49803509889 = 293332^2 + 223167^2 .
It is a cyclic number.
It is not a de Polignac number, because 135847172113 - 217 = 135847041041 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 135847172113.
It is not a weakly prime, because it can be changed into another prime (135847172413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67923586056 + 67923586057.
It is an arithmetic number, because the mean of its divisors is an integer number (67923586057).
Almost surely, 2135847172113 is an apocalyptic number.
It is an amenable number.
135847172113 is a deficient number, since it is larger than the sum of its proper divisors (1).
135847172113 is an equidigital number, since it uses as much as digits as its factorization.
135847172113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 141120, while the sum is 43.
The spelling of 135847172113 in words is "one hundred thirty-five billion, eight hundred forty-seven million, one hundred seventy-two thousand, one hundred thirteen".
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