Base | Representation |
---|---|
bin | 10011110001100001101… |
… | …101010010100100111001 |
3 | 11210220102111222202010012 |
4 | 103301201231102210321 |
5 | 134230410311144212 |
6 | 2520125132231305 |
7 | 200113354212245 |
oct | 23614155224471 |
9 | 4726374882105 |
10 | 1358848928057 |
11 | 484314881925 |
12 | 19b42b90b535 |
13 | 9b1a623166a |
14 | 49aa9207425 |
15 | 255305a4922 |
hex | 13c61b52939 |
1358848928057 has 2 divisors, whose sum is σ = 1358848928058. Its totient is φ = 1358848928056.
The previous prime is 1358848927957. The next prime is 1358848928077. The reversal of 1358848928057 is 7508298488531.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1329729553321 + 29119374736 = 1153139^2 + 170644^2 .
It is an emirp because it is prime and its reverse (7508298488531) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1358848928057 - 218 = 1358848665913 is a prime.
It is not a weakly prime, because it can be changed into another prime (1358848928077) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 679424464028 + 679424464029.
It is an arithmetic number, because the mean of its divisors is an integer number (679424464029).
Almost surely, 21358848928057 is an apocalyptic number.
It is an amenable number.
1358848928057 is a deficient number, since it is larger than the sum of its proper divisors (1).
1358848928057 is an equidigital number, since it uses as much as digits as its factorization.
1358848928057 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 154828800, while the sum is 68.
The spelling of 1358848928057 in words is "one trillion, three hundred fifty-eight billion, eight hundred forty-eight million, nine hundred twenty-eight thousand, fifty-seven".
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