Base | Representation |
---|---|
bin | 10011110010000011011… |
… | …110001110101100010011 |
3 | 11210221212222220202211222 |
4 | 103302003132032230103 |
5 | 134233040320432311 |
6 | 2520301245555255 |
7 | 200133403201424 |
oct | 23620336165423 |
9 | 4727788822758 |
10 | 1359415405331 |
11 | 484585613665 |
12 | 19b569575b2b |
13 | 9b2666c0a09 |
14 | 49b2054564b |
15 | 2556519eadb |
hex | 13c8378eb13 |
1359415405331 has 2 divisors, whose sum is σ = 1359415405332. Its totient is φ = 1359415405330.
The previous prime is 1359415405291. The next prime is 1359415405391. The reversal of 1359415405331 is 1335045149531.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1359415405331 is a prime.
It is a super-2 number, since 2×13594154053312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1359415405391) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 679707702665 + 679707702666.
It is an arithmetic number, because the mean of its divisors is an integer number (679707702666).
Almost surely, 21359415405331 is an apocalyptic number.
1359415405331 is a deficient number, since it is larger than the sum of its proper divisors (1).
1359415405331 is an equidigital number, since it uses as much as digits as its factorization.
1359415405331 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 486000, while the sum is 44.
The spelling of 1359415405331 in words is "one trillion, three hundred fifty-nine billion, four hundred fifteen million, four hundred five thousand, three hundred thirty-one".
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