Base | Representation |
---|---|
bin | 11110111011100000110110… |
… | …100110110110111110100010 |
3 | 122211122110002122222200111110 |
4 | 132323200312212312332202 |
5 | 120312213213302331414 |
6 | 1201151500050124150 |
7 | 40436631654653406 |
oct | 3673406646667642 |
9 | 584573078880443 |
10 | 136031120355234 |
11 | 3a386524131125 |
12 | 1330b8aab80656 |
13 | 5ab98ab136a60 |
14 | 2583d27113106 |
15 | 10ad7356b2459 |
hex | 7bb8369b6fa2 |
136031120355234 has 64 divisors (see below), whose sum is σ = 294633117757440. Its totient is φ = 41621023129920.
The previous prime is 136031120355191. The next prime is 136031120355257. The reversal of 136031120355234 is 432553021130631.
It is a Harshad number since it is a multiple of its sum of digits (39).
It is a junction number, because it is equal to n+sod(n) for n = 136031120355192 and 136031120355201.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1047238639 + ... + 1047368525.
It is an arithmetic number, because the mean of its divisors is an integer number (4603642464960).
Almost surely, 2136031120355234 is an apocalyptic number.
136031120355234 is an abundant number, since it is smaller than the sum of its proper divisors (158601997402206).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
136031120355234 is a wasteful number, since it uses less digits than its factorization.
136031120355234 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 205095.
The product of its (nonzero) digits is 194400, while the sum is 39.
Adding to 136031120355234 its reverse (432553021130631), we get a palindrome (568584141485865).
The spelling of 136031120355234 in words is "one hundred thirty-six trillion, thirty-one billion, one hundred twenty million, three hundred fifty-five thousand, two hundred thirty-four".
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