Base | Representation |
---|---|
bin | 11110111011100010000110… |
… | …001101101111001110011101 |
3 | 122211122120112202010210012021 |
4 | 132323202012031233032131 |
5 | 120312223432210302130 |
6 | 1201152240400340141 |
7 | 40440010033212421 |
oct | 3673420615571635 |
9 | 584576482123167 |
10 | 136032455947165 |
11 | 3a38704a029108 |
12 | 13310002314651 |
13 | 5ab9a61a5403b |
14 | 258401265ab81 |
15 | 10ad7b2a8337a |
hex | 7bb88636f39d |
136032455947165 has 4 divisors (see below), whose sum is σ = 163238947136604. Its totient is φ = 108825964757728.
The previous prime is 136032455947147. The next prime is 136032455947207. The reversal of 136032455947165 is 561749554230631.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 59138883812761 + 76893572134404 = 7690181^2 + 8768898^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-136032455947165 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13603245594712 + ... + 13603245594721.
It is an arithmetic number, because the mean of its divisors is an integer number (40809736784151).
Almost surely, 2136032455947165 is an apocalyptic number.
It is an amenable number.
136032455947165 is a deficient number, since it is larger than the sum of its proper divisors (27206491189439).
136032455947165 is an equidigital number, since it uses as much as digits as its factorization.
136032455947165 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 27206491189438.
The product of its (nonzero) digits is 81648000, while the sum is 61.
The spelling of 136032455947165 in words is "one hundred thirty-six trillion, thirty-two billion, four hundred fifty-five million, nine hundred forty-seven thousand, one hundred sixty-five".
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