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136032455947207 is a prime number
BaseRepresentation
bin11110111011100010000110…
…001101101111001111000111
3122211122120112202010210020211
4132323202012031233033013
5120312223432210302312
61201152240400340251
740440010033212511
oct3673420615571707
9584576482123224
10136032455947207
113a38704a029146
1213310002314687
135ab9a61a54071
14258401265abb1
1510ad7b2a833a7
hex7bb88636f3c7

136032455947207 has 2 divisors, whose sum is σ = 136032455947208. Its totient is φ = 136032455947206.

The previous prime is 136032455947147. The next prime is 136032455947211. The reversal of 136032455947207 is 702749554230631.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 136032455947207 - 211 = 136032455945159 is a prime.

It is a super-2 number, since 2×1360324559472072 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (136032455947277) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68016227973603 + 68016227973604.

It is an arithmetic number, because the mean of its divisors is an integer number (68016227973604).

Almost surely, 2136032455947207 is an apocalyptic number.

136032455947207 is a deficient number, since it is larger than the sum of its proper divisors (1).

136032455947207 is an equidigital number, since it uses as much as digits as its factorization.

136032455947207 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 38102400, while the sum is 58.

The spelling of 136032455947207 in words is "one hundred thirty-six trillion, thirty-two billion, four hundred fifty-five million, nine hundred forty-seven thousand, two hundred seven".