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136035544721 is a prime number
BaseRepresentation
bin111111010110001011…
…0011010111010010001
3111000010112212200111012
41332230112122322101
54212100044412341
6142254401500305
712554042023436
oct1765426327221
9430115780435
10136035544721
115276857821a
1222446041695
13ca9c43727b
146826ccbb8d
153812b6d0eb
hex1fac59ae91

136035544721 has 2 divisors, whose sum is σ = 136035544722. Its totient is φ = 136035544720.

The previous prime is 136035544643. The next prime is 136035544727. The reversal of 136035544721 is 127445530631.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 92027896321 + 44007648400 = 303361^2 + 209780^2 .

It is an emirp because it is prime and its reverse (127445530631) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 136035544721 - 222 = 136031350417 is a prime.

It is not a weakly prime, because it can be changed into another prime (136035544727) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68017772360 + 68017772361.

It is an arithmetic number, because the mean of its divisors is an integer number (68017772361).

Almost surely, 2136035544721 is an apocalyptic number.

It is an amenable number.

136035544721 is a deficient number, since it is larger than the sum of its proper divisors (1).

136035544721 is an equidigital number, since it uses as much as digits as its factorization.

136035544721 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 302400, while the sum is 41.

The spelling of 136035544721 in words is "one hundred thirty-six billion, thirty-five million, five hundred forty-four thousand, seven hundred twenty-one".