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1360404356497 is a prime number
BaseRepresentation
bin10011110010111110011…
…010110001110110010001
311211001102220210200210221
4103302332122301312101
5134242102003401442
62520543334353041
7200200042144114
oct23627632616621
94731386720727
101360404356497
11484a4288027a
1219b7a47bb781
139b39355cb14
1449bb5a1857b
15255c1dec467
hex13cbe6b1d91

1360404356497 has 2 divisors, whose sum is σ = 1360404356498. Its totient is φ = 1360404356496.

The previous prime is 1360404356489. The next prime is 1360404356527. The reversal of 1360404356497 is 7946534040631.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1221734513041 + 138669843456 = 1105321^2 + 372384^2 .

It is a cyclic number.

It is not a de Polignac number, because 1360404356497 - 23 = 1360404356489 is a prime.

It is a super-2 number, since 2×13604043564972 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1360404351497) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 680202178248 + 680202178249.

It is an arithmetic number, because the mean of its divisors is an integer number (680202178249).

Almost surely, 21360404356497 is an apocalyptic number.

It is an amenable number.

1360404356497 is a deficient number, since it is larger than the sum of its proper divisors (1).

1360404356497 is an equidigital number, since it uses as much as digits as its factorization.

1360404356497 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6531840, while the sum is 52.

The spelling of 1360404356497 in words is "one trillion, three hundred sixty billion, four hundred four million, three hundred fifty-six thousand, four hundred ninety-seven".