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136041046149120 = 211357171923314167
BaseRepresentation
bin11110111011101010000110…
…001110110000100000000000
3122211200101201102010020222020
4132323222012032300200000
5120312344030303232440
61201200221022241440
740440432641553120
oct3673520616604000
9584611642106866
10136041046149120
113a38a757a71a72
12133117bb126280
135aba800642088
1425845c947ac80
1510adb16cb33d0
hex7bba863b0800

136041046149120 has 6144 divisors, whose sum is σ = 620836238131200. Its totient is φ = 24665024102400.

The previous prime is 136041046149067. The next prime is 136041046149121. The reversal of 136041046149120 is 21941640140631.

It is a tau number, because it is divible by the number of its divisors (6144).

It is a Harshad number since it is a multiple of its sum of digits (42).

It is not an unprimeable number, because it can be changed into a prime (136041046149121) by changing a digit.

It is a polite number, since it can be written in 511 ways as a sum of consecutive naturals, for example, 2030463375327 + ... + 2030463375393.

It is an arithmetic number, because the mean of its divisors is an integer number (101047564800).

Almost surely, 2136041046149120 is an apocalyptic number.

136041046149120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 136041046149120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (310418119065600).

136041046149120 is an abundant number, since it is smaller than the sum of its proper divisors (484795191982080).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

136041046149120 is a wasteful number, since it uses less digits than its factorization.

136041046149120 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 235 (or 215 counting only the distinct ones).

The product of its (nonzero) digits is 124416, while the sum is 42.

Adding to 136041046149120 its reverse (21941640140631), we get a palindrome (157982686289751).

The spelling of 136041046149120 in words is "one hundred thirty-six trillion, forty-one billion, forty-six million, one hundred forty-nine thousand, one hundred twenty".