Base | Representation |
---|---|
bin | 11110111011101100101000… |
… | …100101101111101100000111 |
3 | 122211200122202020200111022002 |
4 | 132323230220211233230013 |
5 | 120312420120120142403 |
6 | 1201201351205455515 |
7 | 40440560305614410 |
oct | 3673545045575407 |
9 | 584618666614262 |
10 | 136043770084103 |
11 | 3a390925616702 |
12 | 1331223b41159b |
13 | 5abab45a8901b |
14 | 25847a7140807 |
15 | 10adc25ec5188 |
hex | 7bbb2896fb07 |
136043770084103 has 4 divisors (see below), whose sum is σ = 155478594381840. Its totient is φ = 116608945786368.
The previous prime is 136043770084097. The next prime is 136043770084153. The reversal of 136043770084103 is 301480077340631.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 136043770084103 - 216 = 136043770018567 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (136043770084153) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9717412148858 + ... + 9717412148871.
It is an arithmetic number, because the mean of its divisors is an integer number (38869648595460).
Almost surely, 2136043770084103 is an apocalyptic number.
136043770084103 is a deficient number, since it is larger than the sum of its proper divisors (19434824297737).
136043770084103 is an equidigital number, since it uses as much as digits as its factorization.
136043770084103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19434824297736.
The product of its (nonzero) digits is 1016064, while the sum is 47.
The spelling of 136043770084103 in words is "one hundred thirty-six trillion, forty-three billion, seven hundred seventy million, eighty-four thousand, one hundred three".
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