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136043770084103 = 719434824297729
BaseRepresentation
bin11110111011101100101000…
…100101101111101100000111
3122211200122202020200111022002
4132323230220211233230013
5120312420120120142403
61201201351205455515
740440560305614410
oct3673545045575407
9584618666614262
10136043770084103
113a390925616702
121331223b41159b
135abab45a8901b
1425847a7140807
1510adc25ec5188
hex7bbb2896fb07

136043770084103 has 4 divisors (see below), whose sum is σ = 155478594381840. Its totient is φ = 116608945786368.

The previous prime is 136043770084097. The next prime is 136043770084153. The reversal of 136043770084103 is 301480077340631.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 136043770084103 - 216 = 136043770018567 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (136043770084153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9717412148858 + ... + 9717412148871.

It is an arithmetic number, because the mean of its divisors is an integer number (38869648595460).

Almost surely, 2136043770084103 is an apocalyptic number.

136043770084103 is a deficient number, since it is larger than the sum of its proper divisors (19434824297737).

136043770084103 is an equidigital number, since it uses as much as digits as its factorization.

136043770084103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19434824297736.

The product of its (nonzero) digits is 1016064, while the sum is 47.

The spelling of 136043770084103 in words is "one hundred thirty-six trillion, forty-three billion, seven hundred seventy million, eighty-four thousand, one hundred three".

Divisors: 1 7 19434824297729 136043770084103