Base | Representation |
---|---|
bin | 1100011000001110000110… |
… | …1101010001011011100011 |
3 | 1210012010102020121202200121 |
4 | 3012003201231101123203 |
5 | 3240442234220311303 |
6 | 44540243120501111 |
7 | 2603210340562351 |
oct | 306034155213343 |
9 | 53163366552617 |
10 | 13610243135203 |
11 | 4378087482390 |
12 | 163990aa7a797 |
13 | 7795957b0c70 |
14 | 350a4c83c7d1 |
15 | 1890788dc9bd |
hex | c60e1b516e3 |
13610243135203 has 16 divisors (see below), whose sum is σ = 16154498104416. Its totient is φ = 11303438883840.
The previous prime is 13610243135189. The next prime is 13610243135207. The reversal of 13610243135203 is 30253134201631.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13610243135203 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13610243135207) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 490586776 + ... + 490614517.
It is an arithmetic number, because the mean of its divisors is an integer number (1009656131526).
Almost surely, 213610243135203 is an apocalyptic number.
13610243135203 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
13610243135203 is a deficient number, since it is larger than the sum of its proper divisors (2544254969213).
13610243135203 is a wasteful number, since it uses less digits than its factorization.
13610243135203 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 981201414.
The product of its (nonzero) digits is 38880, while the sum is 34.
Adding to 13610243135203 its reverse (30253134201631), we get a palindrome (43863377336834).
The spelling of 13610243135203 in words is "thirteen trillion, six hundred ten billion, two hundred forty-three million, one hundred thirty-five thousand, two hundred three".
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