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13611341 = 47289603
BaseRepresentation
bin110011111011…
…000101001101
3221121112020202
4303323011031
511441030331
61203423245
7223460132
oct63730515
927545222
1013611341
117757447
124684b25
132a87563
141b44589
1512dcecb
hexcfb14d

13611341 has 4 divisors (see below), whose sum is σ = 13900992. Its totient is φ = 13321692.

The previous prime is 13611337. The next prime is 13611343. The reversal of 13611341 is 14311631.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14311631 = 15239397.

It is a cyclic number.

It is not a de Polignac number, because 13611341 - 22 = 13611337 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13611343) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 144755 + ... + 144848.

It is an arithmetic number, because the mean of its divisors is an integer number (3475248).

Almost surely, 213611341 is an apocalyptic number.

It is an amenable number.

13611341 is a deficient number, since it is larger than the sum of its proper divisors (289651).

13611341 is an equidigital number, since it uses as much as digits as its factorization.

13611341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 289650.

The product of its digits is 216, while the sum is 20.

The square root of 13611341 is about 3689.3550926957. The cubic root of 13611341 is about 238.7629694260.

Adding to 13611341 its reverse (14311631), we get a palindrome (27922972).

The spelling of 13611341 in words is "thirteen million, six hundred eleven thousand, three hundred forty-one".

Divisors: 1 47 289603 13611341