Base | Representation |
---|---|
bin | 10011110011101110001… |
… | …011000110011000000100 |
3 | 11211010111202101200022022 |
4 | 103303232023012120010 |
5 | 134300222110141034 |
6 | 2521155035022312 |
7 | 200225641202000 |
oct | 23635613063004 |
9 | 4733452350268 |
10 | 1361205552644 |
11 | 485314058853 |
12 | 19b988b9a998 |
13 | 9b490541292 |
14 | 49c501b5700 |
15 | 2561c40db2e |
hex | 13cee2c6604 |
1361205552644 has 24 divisors (see below), whose sum is σ = 2777970518400. Its totient is φ = 583373807688.
The previous prime is 1361205552631. The next prime is 1361205552653. The reversal of 1361205552644 is 4462555021631.
It is a junction number, because it is equal to n+sod(n) for n = 1361205552595 and 1361205552604.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 496064792 + ... + 496067535.
It is an arithmetic number, because the mean of its divisors is an integer number (115748771600).
Almost surely, 21361205552644 is an apocalyptic number.
1361205552644 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is an amenable number.
1361205552644 is an abundant number, since it is smaller than the sum of its proper divisors (1416764965756).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1361205552644 is an equidigital number, since it uses as much as digits as its factorization.
1361205552644 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 992132352 (or 992132336 counting only the distinct ones).
The product of its (nonzero) digits is 864000, while the sum is 44.
The spelling of 1361205552644 in words is "one trillion, three hundred sixty-one billion, two hundred five million, five hundred fifty-two thousand, six hundred forty-four".
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