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1361250026551 = 4436949442193
BaseRepresentation
bin10011110011110000110…
…100110000010000110111
311211010121212002012001001
4103303300310300100313
5134300320001322201
62521203304144131
7200230021212352
oct23636064602067
94733555065031
101361250026551
11485337174748
1219b99ba68047
139b4998132bc
1449c56071299
1525621296301
hex13cf0d30437

1361250026551 has 8 divisors (see below), whose sum is σ = 1364522245200. Its totient is φ = 1357978707072.

The previous prime is 1361250026537. The next prime is 1361250026561. The reversal of 1361250026551 is 1556200521631.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1361250026551 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1361250026551.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1361250026531) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2857311 + ... + 3299503.

It is an arithmetic number, because the mean of its divisors is an integer number (170565280650).

Almost surely, 21361250026551 is an apocalyptic number.

1361250026551 is a deficient number, since it is larger than the sum of its proper divisors (3272218649).

1361250026551 is an equidigital number, since it uses as much as digits as its factorization.

1361250026551 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 449585.

The product of its (nonzero) digits is 54000, while the sum is 37.

The spelling of 1361250026551 in words is "one trillion, three hundred sixty-one billion, two hundred fifty million, twenty-six thousand, five hundred fifty-one".

Divisors: 1 443 6949 442193 3078407 195891499 3072799157 1361250026551