Base | Representation |
---|---|
bin | 10011110011110000110… |
… | …100111100110000100011 |
3 | 11211010121212011210020121 |
4 | 103303300310330300203 |
5 | 134300320004441411 |
6 | 2521203305221111 |
7 | 200230021514515 |
oct | 23636064746043 |
9 | 4733555153217 |
10 | 1361250077731 |
11 | 4853371aa145 |
12 | 19b99ba91797 |
13 | 9b49983069b |
14 | 49c56085bb5 |
15 | 256212a6571 |
hex | 13cf0d3cc23 |
1361250077731 has 2 divisors, whose sum is σ = 1361250077732. Its totient is φ = 1361250077730.
The previous prime is 1361250077653. The next prime is 1361250077741. The reversal of 1361250077731 is 1377700521631.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1361250077731 - 223 = 1361241689123 is a prime.
It is a super-2 number, since 2×13612500777312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1361250077741) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 680625038865 + 680625038866.
It is an arithmetic number, because the mean of its divisors is an integer number (680625038866).
Almost surely, 21361250077731 is an apocalyptic number.
1361250077731 is a deficient number, since it is larger than the sum of its proper divisors (1).
1361250077731 is an equidigital number, since it uses as much as digits as its factorization.
1361250077731 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 185220, while the sum is 43.
The spelling of 1361250077731 in words is "one trillion, three hundred sixty-one billion, two hundred fifty million, seventy-seven thousand, seven hundred thirty-one".
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