Base | Representation |
---|---|
bin | 111111011001000001… |
… | …1000110001101010001 |
3 | 111000101012202112221222 |
4 | 1332302003012031101 |
5 | 4212244033024411 |
6 | 142312054454425 |
7 | 12556312422215 |
oct | 1766203061521 |
9 | 430335675858 |
10 | 136131142481 |
11 | 52807532234 |
12 | 22472064415 |
13 | cab61990a9 |
14 | 6835894945 |
15 | 381b2534db |
hex | 1fb20c6351 |
136131142481 has 2 divisors, whose sum is σ = 136131142482. Its totient is φ = 136131142480.
The previous prime is 136131142457. The next prime is 136131142493. The reversal of 136131142481 is 184241131631.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 123822349456 + 12308793025 = 351884^2 + 110945^2 .
It is a cyclic number.
It is not a de Polignac number, because 136131142481 - 226 = 136064033617 is a prime.
It is a super-2 number, since 2×1361311424812 (a number of 23 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (136131142181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68065571240 + 68065571241.
It is an arithmetic number, because the mean of its divisors is an integer number (68065571241).
Almost surely, 2136131142481 is an apocalyptic number.
It is an amenable number.
136131142481 is a deficient number, since it is larger than the sum of its proper divisors (1).
136131142481 is an equidigital number, since it uses as much as digits as its factorization.
136131142481 is an evil number, because the sum of its binary digits is even.
The product of its digits is 13824, while the sum is 35.
The spelling of 136131142481 in words is "one hundred thirty-six billion, one hundred thirty-one million, one hundred forty-two thousand, four hundred eighty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •