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1361317252307 is a prime number
BaseRepresentation
bin10011110011110100110…
…101001100110011010011
311211010210112120121102212
4103303310311030303103
5134300434204033212
62521214105102335
7200231465502665
oct23636465146323
94733715517385
101361317252307
11485371110421
1219b9ba4879ab
139b4aa72015c
1449c60d70535
1525627124e22
hex13cf4d4ccd3

1361317252307 has 2 divisors, whose sum is σ = 1361317252308. Its totient is φ = 1361317252306.

The previous prime is 1361317252249. The next prime is 1361317252313. The reversal of 1361317252307 is 7032527131631.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1361317252307 - 28 = 1361317252051 is a prime.

It is a super-2 number, since 2×13613172523072 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1361317252397) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 680658626153 + 680658626154.

It is an arithmetic number, because the mean of its divisors is an integer number (680658626154).

Almost surely, 21361317252307 is an apocalyptic number.

1361317252307 is a deficient number, since it is larger than the sum of its proper divisors (1).

1361317252307 is an equidigital number, since it uses as much as digits as its factorization.

1361317252307 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 158760, while the sum is 41.

The spelling of 1361317252307 in words is "one trillion, three hundred sixty-one billion, three hundred seventeen million, two hundred fifty-two thousand, three hundred seven".