Base | Representation |
---|---|
bin | 10011110011110100110… |
… | …101001100110011010011 |
3 | 11211010210112120121102212 |
4 | 103303310311030303103 |
5 | 134300434204033212 |
6 | 2521214105102335 |
7 | 200231465502665 |
oct | 23636465146323 |
9 | 4733715517385 |
10 | 1361317252307 |
11 | 485371110421 |
12 | 19b9ba4879ab |
13 | 9b4aa72015c |
14 | 49c60d70535 |
15 | 25627124e22 |
hex | 13cf4d4ccd3 |
1361317252307 has 2 divisors, whose sum is σ = 1361317252308. Its totient is φ = 1361317252306.
The previous prime is 1361317252249. The next prime is 1361317252313. The reversal of 1361317252307 is 7032527131631.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1361317252307 - 28 = 1361317252051 is a prime.
It is a super-2 number, since 2×13613172523072 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1361317252397) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 680658626153 + 680658626154.
It is an arithmetic number, because the mean of its divisors is an integer number (680658626154).
Almost surely, 21361317252307 is an apocalyptic number.
1361317252307 is a deficient number, since it is larger than the sum of its proper divisors (1).
1361317252307 is an equidigital number, since it uses as much as digits as its factorization.
1361317252307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 158760, while the sum is 41.
The spelling of 1361317252307 in words is "one trillion, three hundred sixty-one billion, three hundred seventeen million, two hundred fifty-two thousand, three hundred seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •