Base | Representation |
---|---|
bin | 10011110011110101101… |
… | …011111100001100000001 |
3 | 11211010211112120122202112 |
4 | 103303311223330030001 |
5 | 134301001342232202 |
6 | 2521215340425105 |
7 | 200232031460231 |
oct | 23636553741401 |
9 | 4733745518675 |
10 | 1361331602177 |
11 | 485379221718 |
12 | 19ba03248195 |
13 | 9b4b06a58c1 |
14 | 49c62c27cc1 |
15 | 2562850bb52 |
hex | 13cf5afc301 |
1361331602177 has 2 divisors, whose sum is σ = 1361331602178. Its totient is φ = 1361331602176.
The previous prime is 1361331602159. The next prime is 1361331602261. The reversal of 1361331602177 is 7712061331631.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1170743476081 + 190588126096 = 1082009^2 + 436564^2 .
It is a cyclic number.
It is not a de Polignac number, because 1361331602177 - 216 = 1361331536641 is a prime.
It is a super-2 number, since 2×13613316021772 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1361331682177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 680665801088 + 680665801089.
It is an arithmetic number, because the mean of its divisors is an integer number (680665801089).
Almost surely, 21361331602177 is an apocalyptic number.
It is an amenable number.
1361331602177 is a deficient number, since it is larger than the sum of its proper divisors (1).
1361331602177 is an equidigital number, since it uses as much as digits as its factorization.
1361331602177 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 95256, while the sum is 41.
The spelling of 1361331602177 in words is "one trillion, three hundred sixty-one billion, three hundred thirty-one million, six hundred two thousand, one hundred seventy-seven".
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