Base | Representation |
---|---|
bin | 10011110011110110111… |
… | …110000100001111001101 |
3 | 11211010220001002102200202 |
4 | 103303312332010033031 |
5 | 134301022400142312 |
6 | 2521221430103245 |
7 | 200232412454321 |
oct | 23636676041715 |
9 | 4733801072622 |
10 | 1361353130957 |
11 | 48538a3965a6 |
12 | 19ba0a4aab25 |
13 | 9b4b4ca2b21 |
14 | 49c65a2d981 |
15 | 2562a3609c2 |
hex | 13cf6f843cd |
1361353130957 has 4 divisors (see below), whose sum is σ = 1361356680960. Its totient is φ = 1361349580956.
The previous prime is 1361353130867. The next prime is 1361353130989. The reversal of 1361353130957 is 7590313531631.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1361353130957 - 232 = 1357058163661 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1361353133957) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1118957 + ... + 1993682.
It is an arithmetic number, because the mean of its divisors is an integer number (340339170240).
Almost surely, 21361353130957 is an apocalyptic number.
It is an amenable number.
1361353130957 is a deficient number, since it is larger than the sum of its proper divisors (3550003).
1361353130957 is an equidigital number, since it uses as much as digits as its factorization.
1361353130957 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3550002.
The product of its (nonzero) digits is 765450, while the sum is 47.
The spelling of 1361353130957 in words is "one trillion, three hundred sixty-one billion, three hundred fifty-three million, one hundred thirty thousand, nine hundred fifty-seven".
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