Base | Representation |
---|---|
bin | 10011110100000001011… |
… | …001101010111010111111 |
3 | 11211011100020101210012222 |
4 | 103310001121222322333 |
5 | 134301402200430310 |
6 | 2521251041115555 |
7 | 200236636143221 |
oct | 23640131527277 |
9 | 4734306353188 |
10 | 1361528139455 |
11 | 48546a15a020 |
12 | 19ba59028bbb |
13 | 9b512319a53 |
14 | 49c80d88411 |
15 | 2563a8d0055 |
hex | 13d0166aebf |
1361528139455 has 16 divisors (see below), whose sum is σ = 1782482152608. Its totient is φ = 990136704000.
The previous prime is 1361528139443. The next prime is 1361528139527. The reversal of 1361528139455 is 5549318251631.
It is not a de Polignac number, because 1361528139455 - 214 = 1361528123071 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1361528139397 and 1361528139406.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 26135 + ... + 1650375.
It is an arithmetic number, because the mean of its divisors is an integer number (111405134538).
Almost surely, 21361528139455 is an apocalyptic number.
1361528139455 is a deficient number, since it is larger than the sum of its proper divisors (420954013153).
1361528139455 is a wasteful number, since it uses less digits than its factorization.
1361528139455 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1639498.
The product of its digits is 3888000, while the sum is 53.
The spelling of 1361528139455 in words is "one trillion, three hundred sixty-one billion, five hundred twenty-eight million, one hundred thirty-nine thousand, four hundred fifty-five".
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