Base | Representation |
---|---|
bin | 10011110100000010110… |
… | …111001100001011000001 |
3 | 11211011101221112022021122 |
4 | 103310002313030023001 |
5 | 134301424434430131 |
6 | 2521253314402025 |
7 | 200240354420225 |
oct | 23640267141301 |
9 | 4734357468248 |
10 | 1361552655041 |
11 | 485481a83a37 |
12 | 19ba65290315 |
13 | 9b517421607 |
14 | 49c8432a785 |
15 | 2563cb23d7b |
hex | 13d02dcc2c1 |
1361552655041 has 2 divisors, whose sum is σ = 1361552655042. Its totient is φ = 1361552655040.
The previous prime is 1361552654993. The next prime is 1361552655079. The reversal of 1361552655041 is 1405562551631.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1356011341441 + 5541313600 = 1164479^2 + 74440^2 .
It is a cyclic number.
It is not a de Polignac number, because 1361552655041 - 222 = 1361548460737 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1361552654983 and 1361552655001.
It is not a weakly prime, because it can be changed into another prime (1361552654041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 680776327520 + 680776327521.
It is an arithmetic number, because the mean of its divisors is an integer number (680776327521).
Almost surely, 21361552655041 is an apocalyptic number.
It is an amenable number.
1361552655041 is a deficient number, since it is larger than the sum of its proper divisors (1).
1361552655041 is an equidigital number, since it uses as much as digits as its factorization.
1361552655041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 540000, while the sum is 44.
The spelling of 1361552655041 in words is "one trillion, three hundred sixty-one billion, five hundred fifty-two million, six hundred fifty-five thousand, forty-one".
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