Base | Representation |
---|---|
bin | 10011110100011011111… |
… | …111100001101100011011 |
3 | 11211012111022212121022011 |
4 | 103310123333201230123 |
5 | 134303310403130442 |
6 | 2521403215210351 |
7 | 200253664200436 |
oct | 23643377415433 |
9 | 4735438777264 |
10 | 1361974270747 |
11 | 485678a73072 |
12 | 19bb625169b7 |
13 | 9b58389086c |
14 | 49cc431a81d |
15 | 25664b57117 |
hex | 13d1bfe1b1b |
1361974270747 has 2 divisors, whose sum is σ = 1361974270748. Its totient is φ = 1361974270746.
The previous prime is 1361974270739. The next prime is 1361974270759. The reversal of 1361974270747 is 7470724791631.
It is a weak prime.
It is an emirp because it is prime and its reverse (7470724791631) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1361974270747 - 23 = 1361974270739 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1361974270691 and 1361974270700.
It is not a weakly prime, because it can be changed into another prime (1361974270777) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 680987135373 + 680987135374.
It is an arithmetic number, because the mean of its divisors is an integer number (680987135374).
Almost surely, 21361974270747 is an apocalyptic number.
1361974270747 is a deficient number, since it is larger than the sum of its proper divisors (1).
1361974270747 is an equidigital number, since it uses as much as digits as its factorization.
1361974270747 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12446784, while the sum is 58.
The spelling of 1361974270747 in words is "one trillion, three hundred sixty-one billion, nine hundred seventy-four million, two hundred seventy thousand, seven hundred forty-seven".
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